square root

This function is executed : 1/2(7 + 25 / 7). In each step the 7 (startvalue of the addition and 1st divisor) is set to the result of each step and the function is executed again until the result is not changing anymore and the square root of the basic number is found (in the number space of Java : from +- 4.9E-324 to +-1.7976931348623157E+308).

The difference from the Java square root function of the result of every step is shown to see the speed of the function.

Please choose own numbers to see what happens.

This function is an example how a result is found step by step by the calculus. This project is supported by Prof. Dr. Christoph Klauck.